P value for wood area: Chi2=0.58 DF=6 P value equals 0.9653
From these results, our P value indicates that the differences in phenotypes are not significant and therefore we must accept the null hypothesis. Selection is not a factor for the different phenotypic frequencies in the two habitats; rather, it is genetic drift that has caused these differences.
1
Black Green Orange Yellow
6 1 6 7
2
Black Green Orange Red Yellow
5 2 1 9 3
3
Black Green Orange Red Yellow
5 2 4 4 5
4
Black Green Orange Red Yellow
7 1 3 3 6
5
Black Green Orange Red Yellow
5 3 4 3 5
6
Black Green Orange Yellow
6 3 6 5
P value for grass area:
P value equals 0.0419
P value for wood area:
Chi2=0.58 DF=6
P value equals 0.9653
From these results, our P value indicates that the differences in phenotypes are not significant and therefore we must accept the null hypothesis. Selection is not a factor for the different phenotypic frequencies in the two habitats; rather, it is genetic drift that has caused these differences.